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  post #1  
Old 08-05-2008, 03:14 PM
kalex28 kalex28 is offline
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Default problems on age

Reena is twice as old as sunita.Three years ago , she was three times as old as sunita.How old is Reena now?
can anyone solve this problem.
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  post #2  
Old 08-06-2008, 02:41 AM
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let Reena be R and Sunita be S

Reena is twice as old as sunita -> R=2S
Three years ago , she was three times as old as sunita -> R-3 = 3(S-3) <-> R=3S - 6

3S-6 = 2S
S = 6
R = 2*6 =12

so the answer is 12

CMIIW
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Old 08-07-2008, 06:12 PM
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let the age of sunita = x
then, the age of ravina = 2x
three years ago,
ravina's age => 2x= 3(x-3)
2x= 3x-9
ans is 9
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Old 08-07-2008, 06:47 PM
GemmaR GemmaR is offline
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She is 6, and the other one is 3.
So 3 years ago she was twice as old.
I think that's the right answer anyway (:
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Old 08-08-2008, 02:52 AM
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Quote:
Originally Posted by shubham5526 View Post
let the age of sunita = x
then, the age of ravina = 2x
three years ago,
ravina's age => 2x= 3(x-3)
2x= 3x-9
ans is 9
if you do it that way then it's the sunita answer coz from your equation 9 is the value of x and the x is sunita's age while the question is reena's age

@GemmaR: kalex 28 said that 3 years ago she was three times as old not twice

CMIIW
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Old 08-08-2008, 10:41 AM
GemmaR GemmaR is offline
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Oh yeah that was a typo.
I meant to write 3 times
I stick by my answer.
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Old 08-08-2008, 11:30 PM
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X=2Y
X-3=3(Y-3)

Therefore 2y-3=3y-9, y=6
Then X=12

Reena is 12 years old now and sunita is 6 years old now
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Old 08-09-2008, 04:50 PM
poohgal poohgal is offline
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Quote:
Originally Posted by lifeplayer View Post
X=2Y
X-3=3(Y-3)

Therefore 2y-3=3y-9, y=6
Then X=12

Reena is 12 years old now and sunita is 6 years old now
Our answer is the same but I use the ratio approach for this question.

3 years ago - R:S = 3:1 (Difference is 2 units)

Now - R:S = 2:1 (difference is 1 unit)

Since age difference is always the same, I multiply the ratio now by 2 to make the difference the same.

Now - R:S = 4:2 (difference is 2 unit)

As you can see, the ratio of R and S have each increased by 1 unit (from 3 years ago to Now)

This indicates 1 unit - 3 years.
Since R = 4 units, her age is 4X3=12.
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Old 08-09-2008, 05:40 PM
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let R AND S
R=2S ->NOW
3 YEARS AGO S-3
R=3(S-3) = (3S-9)-3
soo
3S-12 = 2S
AND S=12 !!
Sunita is 12 years old and Reena is 24 years old..
that's all.. cased closed.. lol!
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Old 08-11-2008, 05:08 AM
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Quote:
Originally Posted by m4s4mun3 View Post
let R AND S
R=2S ->NOW
3 YEARS AGO S-3
R=3(S-3) = (3S-9)-3
soo
3S-12 = 2S
AND S=12 !!
Sunita is 12 years old and Reena is 24 years old..
that's all.. cased closed.. lol!
gee, if u traced back your answer then 3 years ago, sunita is 9 and reena is 21 while it was said that reena's age is 3 times of sunita 3 years ago.. :hammer:
so you're wrong.. lol
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Old 08-12-2008, 03:57 AM
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Reena is twice as old as sunita. (R = 2 x S)
Three years ago , she was three times as old as sunita. (R - 3 = 3 (S - 3)
replace R wit S
2S - 3 = 3S -9
-3 + 9 = 3S - 2S
6 = S

so Sunita is 6 years old and Reena is 12 years old

GBU
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Old 08-14-2008, 03:05 PM
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Quote:
Originally Posted by toledodol View Post
Reena is twice as old as sunita. (R = 2 x S)
Three years ago , she was three times as old as sunita. (R - 3 = 3 (S - 3)
replace R wit S
2S - 3 = 3S -9
-3 + 9 = 3S - 2S
6 = S

so Sunita is 6 years old and Reena is 12 years old
YES!! I think this is more reasonable... I could understand it.
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